Answer
- 1
We can solve this algebraically. Let \(q\) represent the number of quizzes she had taken previously. Therefore, from the definition of average:
\(96=\frac{93q+99}{q+1}\)
Solving this, we obtain \(96\left(q+1\right)=93q+99.\) This has a solution of \(q=1,\) so there was one quiz prior to yesterday’s quiz.
A student had an average of 93 on her quiz scores. Then she got a 99 on yesterday’s quiz, which raised her quiz-score average to 96. How many quizzes had she taken before yesterday’s quiz?
- 1
- 2
- 3
- 4
- 5
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