Combining Like Terms and Distributive Property

Distributive Property and Combining Like Terms

Distributive Property

I want to briefly revisit a concept that I glossed over earlier. That’s the distributive property. The distributive property applies to all real numbers. Any time you are dealing with real numbers you can use the distributive property. The distributive property says that for any three real numbers (A, B, and C) that A + B × C = A × C + B × C.

It’s called the distributive property, because you’re distributing this number here outside of the sum to each of the terms in the sum. This C is being distributed to A and to B. Because this distributed property works, you have a lot of different tools you can use to simplify expressions. I’m going to demonstrate a couple of those with a polynomial expression.

Let’s take the polynomial expression x3 + 3x2 + 3x3 + 5x2 + 6x. We have this long expression here and we want to simplify it to make it easier to solve an equation that has this in it. To do that, we’re going to apply the distributive property a couple of different ways.

First, we’re going to use this to combine like terms. You’ll notice we have this x3 here plus 3x3. What we can do here is we can do this. Of course, it’s assumed to have a 1 before it. Essentially, we have 1 × x3 + 3 × x3. You’ll notice that’s very similar to what we have up here.

We know that we can rewrite that expression in this format here, or as 1 plus 3, taking the A and B from over here and putting them in parentheses, times C, or x3. This is the same as 4x3. Similarly, with the x2 terms, we can take the 3x2 + 5x2 and once again move from this format to this format.

That will give us 3 + 5 × x2, or 8x2. Now we can rewrite this expression here as 4x3 + 8x2 + 6x. Now that we’ve combined like terms, we just have one term for each power of x, but we can take this one step further yet. Now that we’ve combined like terms, we can pull out some terms that are common to each of these three terms.

If you’ll notice, all three of these coefficients are even, which means that they’re all divisible by 2. We can pull out a 2. They all contain a power an x, so we can pull out an x. Let’s divide each of these terms by 2x and put that outside of the set of parentheses. 4x3 ÷ 2x is going to be 2x2.

Plus we had 8x2 here, so divided by 2x is going to be plus 4x. Then 6x divided by 2x is just going to be three. We’ll multiply that now by 2x, because we pulled the 2x out of each term. Applying the distributive property here to this expression, we were able to simplify it to that form.



by Mometrix Test Preparation | Last Updated: September 11, 2020