Answer
- 0.000216
The probability of the occurrence of consecutive independent events is equal to the product of their probabilities. The probabilities of each toy being defective is 6% = 0.06. Therefore, the probability of 3 toys in a row being defective is \((0.06)(0.06)(0.06)\)\(=0.06^3=0.000216\).
Each time a toy is manufactured, there is a 6% chance that it will be defective. What is the probability that three toys in a row will be defective?
- 0.000216
- 0.0216
- 0.06
- 0.0036
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