# The Best Way to Solve Age Word Problems

Welcome to this video lesson on age word problems. Yes, the dreaded age word problem where you are told a bunch of crazy names and ages in code. But don’t worry, we’ll learn a straightforward way to solve these tricky problems.

Let’s take a look at an example:

“Mike, Gavin, and Bella are siblings. Mike is three years older than twice Bella’s age. Gavin is 5 years younger than Mike. If Bella is 4, describe how to determine the age of each of her siblings.”

Okay, we need to sort through these names and ages before we get confused.

STEP 1: Create a little table of things we know… since there are 3 people let’s put their names down.

STEP 2: Now let’s put their age equations into our table. First let’s say Bella’s age is “x” because the first part of the problem assumes that before giving us her age, so she is x and Mike is twice as old plus 3 years, so he is 2x+3, while Gavin is 5 years younger than Mike, so we use Mike’s age equation but subtract 5.

Bella | Mike | Gavin |

x | 2x + 3 | 2x − 2 |

x = 4 | 2(4) + 3 = 11 | 2(4) − 2 = 6 |

STEP 3. Now that we substitute 4 in for “x”, we can solve for Mike and Gavin. Who are 11 and 6.

I hope that helps. Thanks for watching this video lesson, and, until next time, happy studying.

Provided by:

*Mometrix Test Preparation*

Last updated: 05/30/2018