{"id":97495,"date":"2021-10-13T16:13:31","date_gmt":"2021-10-13T21:13:31","guid":{"rendered":"https:\/\/www.mometrix.com\/academy\/?page_id=97495"},"modified":"2026-05-21T12:56:01","modified_gmt":"2026-05-21T17:56:01","slug":"simplifying-square-roots","status":"publish","type":"page","link":"https:\/\/www.mometrix.com\/academy\/simplifying-square-roots\/","title":{"rendered":"Simplifying Square Roots Overview"},"content":{"rendered":"<p>The square root of a number is a number that, when multiplied by itself, results in the original number. For example, \\(5\\times5=25\\), therefore, the square root of \\(25\\) is \\(5\\). The radical symbol, \\(\\sqrt{ }\\), is used to represent square roots. The two statements, \u201cWhat is the square root of \\(36\\)?\u201d and \u201cWhat is \\(\\sqrt{36}\\)?\u201d are read the exact same way.<\/p>\n<div class=\"buttonlinks\"><a href=\"#pqs\">Simplifying Square Root Sample Questions<\/a><\/div>\n<p>To simplify a square root, we simply find the value that when multiplied by itself gives us the original number. When a number\u2019s square root is a whole number, the original number is called a perfect square.<\/p>\n<p>Here are some examples of perfect squares:<\/p>\n\\(\\sqrt{4}=2\\)\n\\(\\sqrt{9}=3\\)\n\\(\\sqrt{16}=4\\)\n\\(\\sqrt{25}=5\\)\n<p>When a square root does not simplify to a whole number, we simplify what we can and whatever is remaining stays under the radical symbol. For example, to simplify \\(\\sqrt{28}\\), we will look at the factors of \\(\\sqrt{28}\\) to see if there are any perfect squares. \\(28=2\\times2\\times7\\) or \\(4\\times7\\). Since \\(4\\) is a perfect square and \\(\\sqrt{4}=2\\), we can pull that out and we are left with \\(7\\) under the radical, so \\(\\sqrt{28}=2\\sqrt{7}\\).<\/p>\n<h3>Example<\/h3>\n<p>Simplify \\(\\sqrt{180}\\).<\/p>\n<div id=\"pqs\"><\/div>\n\\(180=2\\times2\\times3\\times3\\times5\\)\n<p>Therefore, \\(\\sqrt{180}=2\\times3\\sqrt{5}=6\\sqrt{5}\\).<\/p>\n<a href=\"https:\/\/www.mometrix.com\/university\/mathcr\/?utm_source=academy&amp;utm_medium=inline&amp;utm_campaign=academy-mu-ads&amp;utm_content=mathcr-test\" class=\"class_names\" style=\"color:black;\" onclick=\"_paq.push(['trackEvent', 'Course Button', 'Course Click', 'MathPlacement Course Click']);\"><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter wp-image-57671 size-full\" src=\"https:\/\/www.mometrix.com\/academy\/wp-content\/uploads\/2021\/09\/imcr20-New.png\" alt=\"Click here for 20% off of Mometrix Math College Readiness Online Course. Use code: IMCR20\" width=\"728\" height=\"90\" \/><\/a>\n<h2 class=\"pt-page\">Simplifying Square Root Sample Questions<\/h2>\n<p>Here are a few sample questions going over simplifying square roots.<br \/>\n\n\t\t\t\t<div class=\"PQ\">\n\t\t\t\t\t<strong>Question #1:<\/strong>\n\t\t\t\t\t<div style=\"margin-left:10px;\"><p>&nbsp;<br \/>\nWrite \\(\\sqrt{175}\\) in the most simplified form possible.<\/p>\n<\/div>\n\t\t\t\t\t<div class=\"PQ-Choices\"><div class=\"PQ correct_answer\"  id=\"PQ-1-1\">\\(5\\sqrt{7}\\)<\/div><div class=\"PQ\"  id=\"PQ-1-2\">\\(7\\sqrt{5}\\)<\/div><div class=\"PQ\"  id=\"PQ-1-3\">\\(25\\sqrt{7}\\)<\/div><div class=\"PQ\"  id=\"PQ-1-4\">\\(35\\sqrt{5}\\)<\/div>\n\t\t\t\t\t<\/div>\n\t\t\t\t\t<input id=\"PQ-1\" type=\"checkbox\" class=\"spoiler_button\" \/><label for=\"PQ-1\" style=\"width: 150px;\">Show Answer<\/label>\n\t\t\t\t\t<div class=\"answer\" id=\"PQ-1-spoiler\">\n\t\t\t\t\t\t<strong>Answer:<\/strong><div style=\"margin-left:10px;\"><p>To simplify the expression \\(\\sqrt{175}\\), we will start by finding the factors of \\(175\\), which is \\(5\\times5\\times7\\). Since \\(5\\times5\\) is a perfect square, we can take one \\(5\\) out and we are left with \\(7\\) under the radical; therefore, \\(\\sqrt{175}=5\\sqrt{7}\\).<\/p>\n<\/div>\n\t\t\t\t\t\t<input id=\"PQ-1-hide\" type=\"checkbox\" class=\"spoiler_button\" \/><label for=\"PQ-1-hide\" style=\"width: 150px;\">Hide Answer<\/label>\n\t\t\t\t\t<\/div>\n\t\t\t\t<\/div>\n\t\t\t\t<div class=\"PQ\">\n\t\t\t\t\t<strong>Question #2:<\/strong>\n\t\t\t\t\t<div style=\"margin-left:10px;\"><p>&nbsp;<br \/>\nWhich shows \\(\\sqrt{208}\\) in its most simplified form? <\/p>\n<\/div>\n\t\t\t\t\t<div class=\"PQ-Choices\"><div class=\"PQ\"  id=\"PQ-2-1\">\\(2\\sqrt{52}\\)<\/div><div class=\"PQ\"  id=\"PQ-2-2\">\\(4\\sqrt{52}\\)<\/div><div class=\"PQ correct_answer\"  id=\"PQ-2-3\">\\(4\\sqrt{13}\\)<\/div><div class=\"PQ\"  id=\"PQ-2-4\">\\(13\\sqrt{4}\\)<\/div>\n\t\t\t\t\t<\/div>\n\t\t\t\t\t<input id=\"PQ-2\" type=\"checkbox\" class=\"spoiler_button\" \/><label for=\"PQ-2\" style=\"width: 150px;\">Show Answer<\/label>\n\t\t\t\t\t<div class=\"answer\" id=\"PQ-2-spoiler\">\n\t\t\t\t\t\t<strong>Answer:<\/strong><div style=\"margin-left:10px;\"><p>The simplified form of \\(\\sqrt{208}\\) can be found by first finding the factors of \\(208\\), which is \\(2\\times2\\times2\\times2\\times13\\). There are two perfect squares, \\(2\\times2\\), that we can pull out, which leaves us with \\(13\\) under the radical. Therefore, \\(\\sqrt{208}=4\\sqrt{13}\\).<\/p>\n<\/div>\n\t\t\t\t\t\t<input id=\"PQ-2-hide\" type=\"checkbox\" class=\"spoiler_button\" \/><label for=\"PQ-2-hide\" style=\"width: 150px;\">Hide Answer<\/label>\n\t\t\t\t\t<\/div>\n\t\t\t\t<\/div>\n\t\t\t\t<div class=\"PQ\">\n\t\t\t\t\t<strong>Question #3:<\/strong>\n\t\t\t\t\t<div style=\"margin-left:10px;\"><p>&nbsp;<br \/>\nSimplify \\(\\sqrt{294}\\).<\/p>\n<\/div>\n\t\t\t\t\t<div class=\"PQ-Choices\"><div class=\"PQ\"  id=\"PQ-3-1\">\\(6\\sqrt{7}\\)<\/div><div class=\"PQ correct_answer\"  id=\"PQ-3-2\">\\(7\\sqrt{6}\\)<\/div><div class=\"PQ\"  id=\"PQ-3-3\">\\(14\\sqrt{21}\\)<\/div><div class=\"PQ\"  id=\"PQ-3-4\">\\(21\\sqrt{14}\\)<\/div>\n\t\t\t\t\t<\/div>\n\t\t\t\t\t<input id=\"PQ-3\" type=\"checkbox\" class=\"spoiler_button\" \/><label for=\"PQ-3\" style=\"width: 150px;\">Show Answer<\/label>\n\t\t\t\t\t<div class=\"answer\" id=\"PQ-3-spoiler\">\n\t\t\t\t\t\t<strong>Answer:<\/strong><div style=\"margin-left:10px;\"><p>We will simplify \\(\\sqrt{294}\\) by first finding the factors of \\(294\\), which is \\(2\\times3\\times7\\times7\\). There is one perfect square, \\(7\\times7\\), so we pull one out and we are left with \\(2\\times3\\), or \\(6\\), under the radical. Therefore, \\(\\sqrt{294}=7\\sqrt{6}\\).<\/p>\n<\/div>\n\t\t\t\t\t\t<input id=\"PQ-3-hide\" type=\"checkbox\" class=\"spoiler_button\" \/><label for=\"PQ-3-hide\" style=\"width: 150px;\">Hide Answer<\/label>\n\t\t\t\t\t<\/div>\n\t\t\t\t<\/div>\n\t\t\t\t<div class=\"PQ\">\n\t\t\t\t\t<strong>Question #4:<\/strong>\n\t\t\t\t\t<div style=\"margin-left:10px;\"><p>&nbsp;<br \/>\nHere is an expression: \\(\\sqrt{648}\\). Which shows the expression in its most simplified form?<\/p>\n<\/div>\n\t\t\t\t\t<div class=\"PQ-Choices\"><div class=\"PQ\"  id=\"PQ-4-1\">\\(2\\sqrt{18}\\)<\/div><div class=\"PQ\"  id=\"PQ-4-2\">\\(9\\sqrt{8}\\)<\/div><div class=\"PQ\"  id=\"PQ-4-3\">\\(12\\sqrt{54}\\)<\/div><div class=\"PQ correct_answer\"  id=\"PQ-4-4\">\\(18\\sqrt{2}\\)<\/div>\n\t\t\t\t\t<\/div>\n\t\t\t\t\t<input id=\"PQ-4\" type=\"checkbox\" class=\"spoiler_button\" \/><label for=\"PQ-4\" style=\"width: 150px;\">Show Answer<\/label>\n\t\t\t\t\t<div class=\"answer\" id=\"PQ-4-spoiler\">\n\t\t\t\t\t\t<strong>Answer:<\/strong><div style=\"margin-left:10px;\"><p>To find the most simplified form of the expression \\(\\sqrt{648}\\), we will start by finding the factors of \\(648\\), which is \\(2\\times2\\times2\\times3\\times3\\times3\\times3\\). There are three sets of perfect squares, \\(4,9,\\) and \\(9\\), which we will pull out, and we are going to be left with \\(2\\) under the radical. Therefore, \\(\\sqrt{648}=18\\sqrt{2}\\).<\/p>\n<\/div>\n\t\t\t\t\t\t<input id=\"PQ-4-hide\" type=\"checkbox\" class=\"spoiler_button\" \/><label for=\"PQ-4-hide\" style=\"width: 150px;\">Hide Answer<\/label>\n\t\t\t\t\t<\/div>\n\t\t\t\t<\/div>\n\t\t\t\t<div class=\"PQ\">\n\t\t\t\t\t<strong>Question #5:<\/strong>\n\t\t\t\t\t<div style=\"margin-left:10px;\"><p>&nbsp;<br \/>\nWhich shows \\(\\sqrt{2{,}448}\\) in its most simplified form?<\/p>\n<\/div>\n\t\t\t\t\t<div class=\"PQ-Choices\"><div class=\"PQ\"  id=\"PQ-5-1\">\\(4\\sqrt{51}\\)<\/div><div class=\"PQ correct_answer\"  id=\"PQ-5-2\">\\(12\\sqrt{17}\\)<\/div><div class=\"PQ\"  id=\"PQ-5-3\">\\(17\\sqrt{12}\\)<\/div><div class=\"PQ\"  id=\"PQ-5-4\">\\(48\\sqrt{17}\\)<\/div>\n\t\t\t\t\t<\/div>\n\t\t\t\t\t<input id=\"PQ-5\" type=\"checkbox\" class=\"spoiler_button\" \/><label for=\"PQ-5\" style=\"width: 150px;\">Show Answer<\/label>\n\t\t\t\t\t<div class=\"answer\" id=\"PQ-5-spoiler\">\n\t\t\t\t\t\t<strong>Answer:<\/strong><div style=\"margin-left:10px;\"><p>The most simplified form of the expression \\(\\sqrt{2{,}448}\\) can be found by first finding the factors of \\(2{,}448\\), which is \\(2\\times2\\times2\\times2\\times3\\times3\\times17\\). There are three sets of perfect squares, \\(4,4,\\) and \\(9\\), which we will pull out from under the radical, and will be left with \\(17\\). Therefore, \\(\\sqrt{2{,}448}=12\\sqrt{17}\\).<\/p>\n<\/div>\n\t\t\t\t\t\t<input id=\"PQ-5-hide\" type=\"checkbox\" class=\"spoiler_button\" \/><label for=\"PQ-5-hide\" style=\"width: 150px;\">Hide Answer<\/label>\n\t\t\t\t\t<\/div>\n\t\t\t\t<\/div><\/p>\n<div class=\"home-buttons\">\n<p><a href=\"https:\/\/www.mometrix.com\/academy\/math-sample-questions\/\">Return to Math Sample Questions<\/a><\/p>\n<\/div>\n","protected":false},"excerpt":{"rendered":"<p>The square root of a number is a number that, when multiplied by itself, results in the original number. For example, , therefore, the square root of is . The radical symbol, , is used to represent square roots. The two statements, \u201cWhat is the square root of ?\u201d and \u201cWhat is ?\u201d are read &#8230; <a title=\"Simplifying Square Roots Overview\" class=\"read-more\" href=\"https:\/\/www.mometrix.com\/academy\/simplifying-square-roots\/\" aria-label=\"Read more about Simplifying Square Roots Overview\">Read more<\/a><\/p>\n","protected":false},"author":13,"featured_media":0,"parent":0,"menu_order":0,"comment_status":"closed","ping_status":"closed","template":"","meta":{"footnotes":""},"class_list":{"0":"post-97495","1":"page","2":"type-page","3":"status-publish","5":"page_category-math-advertising-group","6":"page_category-math-non-video-pages","7":"page_type-topic-overview","8":"subject_matter-math"},"aioseo_notices":[],"_links":{"self":[{"href":"https:\/\/www.mometrix.com\/academy\/wp-json\/wp\/v2\/pages\/97495","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.mometrix.com\/academy\/wp-json\/wp\/v2\/pages"}],"about":[{"href":"https:\/\/www.mometrix.com\/academy\/wp-json\/wp\/v2\/types\/page"}],"author":[{"embeddable":true,"href":"https:\/\/www.mometrix.com\/academy\/wp-json\/wp\/v2\/users\/13"}],"replies":[{"embeddable":true,"href":"https:\/\/www.mometrix.com\/academy\/wp-json\/wp\/v2\/comments?post=97495"}],"version-history":[{"count":7,"href":"https:\/\/www.mometrix.com\/academy\/wp-json\/wp\/v2\/pages\/97495\/revisions"}],"predecessor-version":[{"id":295733,"href":"https:\/\/www.mometrix.com\/academy\/wp-json\/wp\/v2\/pages\/97495\/revisions\/295733"}],"wp:attachment":[{"href":"https:\/\/www.mometrix.com\/academy\/wp-json\/wp\/v2\/media?parent=97495"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}