{"id":696,"date":"2013-05-28T14:37:08","date_gmt":"2013-05-28T14:37:08","guid":{"rendered":"http:\/\/www.mometrix.com\/academy\/?page_id=696"},"modified":"2026-03-25T11:43:03","modified_gmt":"2026-03-25T16:43:03","slug":"the-substitution-method","status":"publish","type":"page","link":"https:\/\/www.mometrix.com\/academy\/the-substitution-method\/","title":{"rendered":"What is the Substitution Method?"},"content":{"rendered":"\n\t\t\t<div id=\"mmDeferVideoEncompass_W6NXOJxcd98\" style=\"position: relative;\">\n\t\t\t<picture>\n\t\t\t\t<source srcset=\"https:\/\/www.mometrix.com\/academy\/wp-content\/uploads\/2023\/01\/circle-play-duotone.webp\" type=\"image\/webp\">\n\t\t\t\t<source srcset=\"https:\/\/www.mometrix.com\/academy\/wp-content\/uploads\/2023\/01\/circle-play-duotone.png\" type=\"image\/jpeg\"> \n\t\t\t\t<img fetchpriority=\"high\" decoding=\"async\" loading=\"eager\" id=\"videoThumbnailImage_W6NXOJxcd98\" data-source-videoID=\"W6NXOJxcd98\" src=\"https:\/\/www.mometrix.com\/academy\/wp-content\/uploads\/2023\/01\/circle-play-duotone.png\" alt=\"What is the Substitution Method? 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If you are considering linear equations, then there will only be one point of intersection, unless the lines are parallel, in which case there would be zero points of intersection. If you are considering equations of a higher degree, there may be more points of intersection.<\/p>\n<p>There are four methods of solving systems of equations: graphing, substitution, elimination, and matrix. Today we will focus on the substitution method, specifically in regards to two linear equations.<\/p>\n<p>When using the substitution method, we are going to substitute one of our variables with an expression using the other variable. What do I mean exactly? Well, you want to solve one of your equations so that either \\(x\\) or \\(y\\) is by itself on one side, and then plug that expression into your other equation and solve from there.<\/p>\n<p>Let\u2019s look at a few examples to see what I\u2019m talking about.<\/p>\n<h2><span id=\"Example_1\" class=\"m-toc-anchor\"><\/span>Example #1<\/h2>\n<p>\nSolve the following system of equations.<\/p>\n<div class=\"examplesentence\">\\(x=2y+7\\)<br \/>\n\\(2x+3y=14\\)<\/div>\n<p>\n&nbsp;<br \/>\nOur first step is to make one of our equations have either an \\(x\\) or a \\(y\\) by itself on one side. For this example, we have already been given an equation like that, \\(x=2y+7\\), so we won\u2019t have to do any extra manipulating.<\/p>\n<p>Now we want to think for a minute about what the equals sign means. The equals sign is telling us that the values on either side of the equation equals the other side; they&#8217;re the same! So, in our example, \\(x\\) is the same as \\(2y+7\\). Knowing that, we can then substitute \\(2y+7\\) in for \\(x\\) in our second equation, like this:<\/p>\n<div class=\"examplesentence\">\\(2(2y+7)+3y=14\\)<\/div>\n<p>\n&nbsp;<br \/>\nNow we are left with only one variable in our equation, so we can follow the normal steps of solving an equation to find out what our y-value is.<\/p>\n<div class=\"examplesentence\">\\(4y+14+3y=14\\)<\/div>\n<p>\n&nbsp;<br \/>\nSo \\(4y+3y=7y\\).<\/p>\n<div class=\"examplesentence\">\\(7y+14=14\\)<\/div>\n<p>\n&nbsp;<br \/>\nIf we subtract 14 from both sides, we get \\(7y=0\\), and when we divide by 7 on both sides, we\u2019re left with \\(y=0\\).<\/p>\n<p>Remember, solving a system of equations means finding the point where these two equations intersect. That means that we only have half of our answer. <\/p>\n<p>Our \\(y\\)-coordinate for this point is 0, but we still need to find our \\(x\\)-coordinate. We do this by substituting our newly found \\(y\\)-value in for \\(y\\) in either of our original equations and solving for \\(x\\). I\u2019m going to use our first equation because it will take less manipulating to get our \\(x\\).<\/p>\n<div class=\"examplesentence\">\\(x=2(0)+7=0+7=7\\)<\/div>\n<p>\n&nbsp;<br \/>\nSo our \\(x\\)-coordinate for this point is 7. That means our final answer, the point of intersection for these two lines is \\((7,0)\\).<\/p>\n<h2><span id=\"Example_2\" class=\"m-toc-anchor\"><\/span>Example #2<\/h2>\n<p>\nLet\u2019s look at another example so we can get some more practice using this method.<\/p>\n<div class=\"examplesentence\">\\(9x-3y=12\\)<br \/>\n\\(-6x+8y=4\\)<\/div>\n<p>\n&nbsp;<br \/>\nNeither one of our equations is set up where \\(x\\) or \\(y\\) is on one side by itself, so we are going to have to manipulate one of them to make it that way. I am going to solve our first equation for \\(y\\). <\/p>\n<p>I\u2019m gonna subtract 9\\(x\\) from both sides. This gives us \\(-3y=12-9x\\).<\/p>\n<p>Then, divide by -3 on both sides, which gives us \\(y=3x-4\\).<\/p>\n<p>Now we can substitute this expression in for \\(y\\) in our other equation.<\/p>\n<div class=\"examplesentence\">\\(-6x+8(3x-4)=4\\)<br \/>\n\\(-6x+24x-32=4\\)<\/div>\n<p>\n&nbsp;<br \/>\nAnd when we add these two together, we get \\(18x-32=4\\). Add 32 to both sides to get \\(18x=36\\).<\/p>\n<p>Then, divide by 18 on both sides to get \\(x=2\\).<\/p>\n<p>Now that we have our \\(x\\)-value, we can plug this number into the equation we found for \\(y\\) earlier to get our \\(y\\)-value:<\/p>\n<div class=\"examplesentence\">\\(y=3(2)-4=6-4=2\\)<\/div>\n<p>\n&nbsp;<br \/>\nSo our final point is \\((2,2)\\).<\/p>\n<h2><span id=\"Example_3\" class=\"m-toc-anchor\"><\/span>Example #3<\/h2>\n<p>\nBefore I ask you to try one more on your own, let\u2019s do one more example together.<\/p>\n<div class=\"examplesentence\">\\(8x-3y=14\\)<br \/>\n\\(2x+y=7\\)<\/div>\n<p>\n&nbsp;<br \/>\nFirst, solve one of the equations so there is an independent variable on one side. I\u2019m going to solve the second equation for \\(y\\).<\/p>\n<div class=\"examplesentence\">\\(y=7-2x\\)<\/div>\n<p>\n&nbsp;<br \/>\nNow, we plug in this expression for \\(y\\) in our first equation and solve for \\(x\\).<\/p>\n<div class=\"examplesentence\">\\(8x-3(7-2x)=14\\)<br \/>\n\\(8x-21+6x=14\\)<br \/>\n\\(14x-21=14\\)<br \/>\n\\(14x=35\\)<br \/>\n\\(x=\\frac{35}{14}=\\frac{5}{2}\\)<\/div>\n<p>\n&nbsp;<br \/>\nFinally, we plug in our \\(x\\)-value to our equation for \\(y\\), and solve for \\(y\\).<\/p>\n<div class=\"examplesentence\">\\(y=7-2(\\frac{5}{2})=7-5=2\\)<\/div>\n<p>\n&nbsp;<br \/>\nSo our final point is \\((\\frac{5}{2}, 2)\\).<\/p>\n<h2><span id=\"Example_4\" class=\"m-toc-anchor\"><\/span>Example #4<\/h2>\n<p>\nNow that we\u2019ve gone through three examples together, I want you to try one on your own. After I give you the equations, pause the video and try to solve it on your own. Then, once you have your answer, press play and see if it matches up with mine.<\/p>\n<div class=\"examplesentence\">\\(x+5y=7\\)<br \/>\n\\(7x-2y=12\\)<\/div>\n<p>\n&nbsp;<br \/>\nReady to check your answer?<\/p>\n<p>First, we want to solve one of our equations for an independent variable. I\u2019m going to solve the first equation for \\(x\\).<\/p>\n<div class=\"examplesentence\">\\(x=7-5y\\)<\/div>\n<p>\n&nbsp;<br \/>\nNow, substitute this expression into the second equation.<\/p>\n<div class=\"examplesentence\">\\(7(7-5y)-2y=12\\)<br \/>\n\\(49-35y-2y=12\\)<br \/>\n\\(49-37y=12\\)<br \/>\n\\(-37y=-37\\)<br \/>\n\\(y=1\\)<\/div>\n<p>\n&nbsp;<br \/>\nThen, plug the y-value into the equation for x and solve for the \\(x\\)-coordinate.<\/p>\n<div class=\"examplesentence\">\\(x=7-5(1)=7-5=2\\)<\/div>\n<p>\n&nbsp;<br \/>\nSo our final answer for the system of equations is \\((2,1)\\).<\/p>\n<hr>\n<p>\nWe only looked at examples with two linear equations, but this method can be used for more than two equations and for equations with higher degrees. Simply follow the same steps covered in this video.<\/p>\n<p>Solve equations for independent variables and then substitute them into the other equations until you get a singular variable to solve for. Once you have that variable known, work backward to find all the other variables.<br \/>\nI hope this review of the substitution method was helpful.<\/p>\n<p>Thanks for watching and happy studying!<\/p>\n<\/div>\n<div class=\"spoiler\" id=\"PQs-spoiler\">\n<h2 style=\"text-align:center\"><span id=\"Substitution_Method_Practice_Questions\" class=\"m-toc-anchor\"><\/span>Substitution Method Practice Questions<\/h2>\n\n\t\t\t\t<div class=\"PQ\">\n\t\t\t\t\t<strong>Question #1:<\/strong>\n\t\t\t\t\t<div style=\"margin-left:10px;\"><p>&nbsp;<br \/>\nSolve the following system of equations using the substitution method.<\/p>\n<div class=\"yellow-math-quote\">\\(\\begin{cases}y=2x-14\\\\8x+3y=14\\end{cases}\\)<\/div>\n<\/div>\n\t\t\t\t\t<div class=\"PQ-Choices\"><div class=\"PQ\"  id=\"PQ-1-1\">\\((-6,4)\\)<\/div><div class=\"PQ\"  id=\"PQ-1-2\">\\((12,-11)\\)<\/div><div class=\"PQ correct_answer\"  id=\"PQ-1-3\">\\((4,-6)\\)<\/div><div class=\"PQ\"  id=\"PQ-1-4\">\\((-11,12)\\)<\/div>\n\t\t\t\t\t<\/div>\n\t\t\t\t\t<input id=\"PQ-1\" type=\"checkbox\" class=\"spoiler_button\" \/><label for=\"PQ-1\" style=\"width: 150px;\">Show Answer<\/label>\n\t\t\t\t\t<div class=\"answer\" id=\"PQ-1-spoiler\">\n\t\t\t\t\t\t<strong>Answer:<\/strong><div style=\"margin-left:10px;\"><p>To use the substitution method, first solve one of the equations for an independent variable. The first equation is given to us like this. Substitute \\(2x-14\\) in for \\(y\\) in the second equation and solve for \\(x\\).<\/p>\n<p style=\"text-align: center; line-height: 35px\">\n\\(8x+3(2x-14)=14\\)<br \/>\n\\(8x+6x-42=14\\)<br \/>\n\\(14x-42=14\\)<br \/>\n\\(14x=56\\)<br \/>\n\\(x=4\\)<\/p>\n<p>Then, substitute 4 in for \\(x\\) in the first equation.<\/p>\n<p style=\"text-align: center; line-height: 35px\">\\(y=2(4)-14\\)\\(\\:=8-14=-6\\)<\/p>\n<p>The two lines intersect at the point \\((4,-6)\\).<\/p>\n<\/div>\n\t\t\t\t\t\t<input id=\"PQ-1-hide\" type=\"checkbox\" class=\"spoiler_button\" \/><label for=\"PQ-1-hide\" style=\"width: 150px;\">Hide Answer<\/label>\n\t\t\t\t\t<\/div>\n\t\t\t\t<\/div>\n\t\t\t\t<div class=\"PQ\">\n\t\t\t\t\t<strong>Question #2:<\/strong>\n\t\t\t\t\t<div style=\"margin-left:10px;\"><p>&nbsp;<br \/>\nSolve the following system of equations using the substitution method.<\/p>\n<div class=\"yellow-math-quote\">\\(\\begin{cases}12x-7y=16\\\\-8x+4y=8\\end{cases}\\)<\/div>\n<\/div>\n\t\t\t\t\t<div class=\"PQ-Choices\"><div class=\"PQ correct_answer\"  id=\"PQ-2-1\">\\((-15,-28)\\)<\/div><div class=\"PQ\"  id=\"PQ-2-2\">\\((5,-28)\\)<\/div><div class=\"PQ\"  id=\"PQ-2-3\">\\((-15,7)\\)<\/div><div class=\"PQ\"  id=\"PQ-2-4\">\\((5,7)\\)<\/div>\n\t\t\t\t\t<\/div>\n\t\t\t\t\t<input id=\"PQ-2\" type=\"checkbox\" class=\"spoiler_button\" \/><label for=\"PQ-2\" style=\"width: 150px;\">Show Answer<\/label>\n\t\t\t\t\t<div class=\"answer\" id=\"PQ-2-spoiler\">\n\t\t\t\t\t\t<strong>Answer:<\/strong><div style=\"margin-left:10px;\"><p>To solve this system, first rearrange the second equation so \\(y\\) is isolated on one side.<\/p>\n<p style=\"text-align: center; line-height: 35px\">\n\\(-8x+4y=8\\)<br \/>\n\\(4y=8x+8\\)<br \/>\n\\(y=2x+2\\)<\/p>\n<p>Then, substitute \\(2x+2\\) for \\(y\\) in the first equation and solve for \\(x\\).<\/p>\n<p style=\"text-align: center; line-height: 35px\">\n\\(12x-7(2x+2)=16\\)<br \/>\n\\(12x-14x-14=16\\)<br \/>\n\\(-2x-14=16\\)<br \/>\n\\(-2x=30\\)<br \/>\n\\(x=-15\\)<\/p>\n<p>Finally, substitute \u221215 for \\(x\\) in the rearranged second equation.<\/p>\n<p style=\"text-align: center; line-height: 35px\">\\(y=2(-15)+2\\)\\(\\:=-30+2=-28\\)<\/p>\n<p>The two lines intersect at the point \\((-15,-28)\\).<\/p>\n<\/div>\n\t\t\t\t\t\t<input id=\"PQ-2-hide\" type=\"checkbox\" class=\"spoiler_button\" \/><label for=\"PQ-2-hide\" style=\"width: 150px;\">Hide Answer<\/label>\n\t\t\t\t\t<\/div>\n\t\t\t\t<\/div>\n\t\t\t\t<div class=\"PQ\">\n\t\t\t\t\t<strong>Question #3:<\/strong>\n\t\t\t\t\t<div style=\"margin-left:10px;\"><p>&nbsp;<br \/>\nSolve the following system of equations using the substitution method.<\/p>\n<div class=\"yellow-math-quote\">\\(\\begin{cases}-10x-15y=75\\\\x-y=-25\\end{cases}\\)<\/div>\n<\/div>\n\t\t\t\t\t<div class=\"PQ-Choices\"><div class=\"PQ\"  id=\"PQ-3-1\">\\((-7,6)\\)<\/div><div class=\"PQ\"  id=\"PQ-3-2\">\\((7,-2)\\)<\/div><div class=\"PQ\"  id=\"PQ-3-3\">\\((9,-7)\\)<\/div><div class=\"PQ correct_answer\"  id=\"PQ-3-4\">\\((-18,7)\\)<\/div>\n\t\t\t\t\t<\/div>\n\t\t\t\t\t<input id=\"PQ-3\" type=\"checkbox\" class=\"spoiler_button\" \/><label for=\"PQ-3\" style=\"width: 150px;\">Show Answer<\/label>\n\t\t\t\t\t<div class=\"answer\" id=\"PQ-3-spoiler\">\n\t\t\t\t\t\t<strong>Answer:<\/strong><div style=\"margin-left:10px;\"><p>To solve this system, rearrange the second equation so \\(x\\) is isolated on one side.<\/p>\n<p style=\"text-align:center; line-height: 35px\">\n\\(x-y=-25\\)<br \/>\n\\(x=y-25\\)<\/p>\n<p>Then, substitute \\(y-25\\) for \\(x\\) in the first equation and solve for \\(y\\).<\/p>\n<p style=\"text-align:center; line-height: 35px\">\n\\(-10(y-25)-15y=75\\)<br \/>\n\\(-10y+250-15y=75\\)<br \/>\n\\(-25y+250=75\\)<br \/>\n\\(-25y=-175\\)<br \/>\n\\(y=7\\)<\/p>\n<p>Finally, substitute 7 in for \\(y\\) in the rearranged second equation and solve for \\(x\\).<\/p>\n<p style=\"text-align:center;\">\\(x=(7)-25=-18\\)<\/p>\n<p>The point where these two lines intersect in \\((-18,7)\\).<\/p>\n<\/div>\n\t\t\t\t\t\t<input id=\"PQ-3-hide\" type=\"checkbox\" class=\"spoiler_button\" \/><label for=\"PQ-3-hide\" style=\"width: 150px;\">Hide Answer<\/label>\n\t\t\t\t\t<\/div>\n\t\t\t\t<\/div>\n\t\t\t\t<div class=\"PQ\">\n\t\t\t\t\t<strong>Question #4:<\/strong>\n\t\t\t\t\t<div style=\"margin-left:10px;\"><p>&nbsp;<br \/>\nSolve the following system of equations using the substitution method.<\/p>\n<div class=\"yellow-math-quote\">\\(\\begin{cases}18y-11x=12\\\\2x-3y=9\\end{cases}\\)<\/div>\n<\/div>\n\t\t\t\t\t<div class=\"PQ-Choices\"><div class=\"PQ correct_answer\"  id=\"PQ-4-1\">\\((66,41)\\)<\/div><div class=\"PQ\"  id=\"PQ-4-2\">\\((23,19)\\)<\/div><div class=\"PQ\"  id=\"PQ-4-3\">\\((11,27)\\)<\/div><div class=\"PQ\"  id=\"PQ-4-4\">\\((59,87)\\)<\/div>\n\t\t\t\t\t<\/div>\n\t\t\t\t\t<input id=\"PQ-4\" type=\"checkbox\" class=\"spoiler_button\" \/><label for=\"PQ-4\" style=\"width: 150px;\">Show Answer<\/label>\n\t\t\t\t\t<div class=\"answer\" id=\"PQ-4-spoiler\">\n\t\t\t\t\t\t<strong>Answer:<\/strong><div style=\"margin-left:10px;\"><p>To solve this system, first rearrange the second equation so \\(y\\) is isolated on one side.<\/p>\n<p style=\"text-align: center; line-height: 35px\">\n\\(2x-3y=9\\)<br \/>\n\\(-3y=-2x+9\\)<br \/>\n\\(3y=2x-9\\)<br \/>\n\\(y=\\frac{2}{3}x-3\\)<\/p>\n<p>Then, substitute \\(\\frac{2}{3}x-3\\) for \\(y\\) in the first equation and solve for \\(x\\).<\/p>\n<p style=\"text-align: center; line-height: 35px\">\n\\(18(\\frac{2}{3}x-3)-11x=12\\)<br \/>\n\\(12x-54-11x=12\\)<br \/>\n\\(x-54=12\\)<br \/>\n\\(x=66\\)<\/p>\n<p>Finally, substitute 66 in for \\(x\\) in the rearranged second equation.<\/p>\n<p style=\"text-align: center; line-height: 35px\">\\(y=\\frac{2}{3}(66)-3\\)\\(\\:=44-3=41\\)<\/p>\n<p>The point where the two lines intersect is \\((66,41)\\).<\/p>\n<\/div>\n\t\t\t\t\t\t<input id=\"PQ-4-hide\" type=\"checkbox\" class=\"spoiler_button\" \/><label for=\"PQ-4-hide\" style=\"width: 150px;\">Hide Answer<\/label>\n\t\t\t\t\t<\/div>\n\t\t\t\t<\/div>\n\t\t\t\t<div class=\"PQ\">\n\t\t\t\t\t<strong>Question #5:<\/strong>\n\t\t\t\t\t<div style=\"margin-left:10px;\"><p>&nbsp;<br \/>\nSolve the following system of equations using the substitution method.<\/p>\n<div class=\"yellow-math-quote\">\\(\\begin{cases}x-3y=17\\\\2x-9y=-41\\end{cases}\\)<\/div>\n<\/div>\n\t\t\t\t\t<div class=\"PQ-Choices\"><div class=\"PQ\"  id=\"PQ-5-1\">\\((87,63)\\)<\/div><div class=\"PQ\"  id=\"PQ-5-2\">\\((8,5)\\)<\/div><div class=\"PQ correct_answer\"  id=\"PQ-5-3\">\\((92,25)\\)<\/div><div class=\"PQ\"  id=\"PQ-5-4\">\\((74,81)\\)<\/div>\n\t\t\t\t\t<\/div>\n\t\t\t\t\t<input id=\"PQ-5\" type=\"checkbox\" class=\"spoiler_button\" \/><label for=\"PQ-5\" style=\"width: 150px;\">Show Answer<\/label>\n\t\t\t\t\t<div class=\"answer\" id=\"PQ-5-spoiler\">\n\t\t\t\t\t\t<strong>Answer:<\/strong><div style=\"margin-left:10px;\"><p>To solve this system, first rearrange the first equation so \\(x\\) is isolated on one side.<\/p>\n<p style=\"text-align: center; line-height: 35px\">\n\\(x-3y=17\\)<br \/>\n\\(x=3y+17\\)<\/p>\n<p>Then, substitute \\(3y+17\\) for \\(x\\) in the second equation and solve for \\(y\\).<\/p>\n<p style=\"text-align: center; line-height: 35px\">\n\\(2(3y+17)-9y=-41\\)<br \/>\n\\(6y+34-9y=-41\\)<br \/>\n\\(-3y+34=-41\\)<br \/>\n\\(-3y=-75\\)<br \/>\n\\(y=25\\)<\/p>\n<p>Finally, substitute 25 for \\(y\\) in the rearranged first equation and solve for \\(x\\).<\/p>\n<p style=\"text-align: center; line-height: 35px\">\\(x=3(25)+17\\)\\(\\:=75+17=92\\)<\/p>\n<p>The point where these two lines intersect is \\((92,25)\\).<\/p>\n<\/div>\n\t\t\t\t\t\t<input id=\"PQ-5-hide\" type=\"checkbox\" class=\"spoiler_button\" \/><label for=\"PQ-5-hide\" style=\"width: 150px;\">Hide Answer<\/label>\n\t\t\t\t\t<\/div>\n\t\t\t\t<\/div><\/div>\n<\/div>\n\n<div class=\"home-buttons\">\n<p><a href=\"https:\/\/www.mometrix.com\/academy\/algebra-i\/\">Return to Algebra I Videos<\/a><\/p>\n<\/div>\n","protected":false},"excerpt":{"rendered":"<p>Return to Algebra I Videos<\/p>\n","protected":false},"author":1,"featured_media":187040,"parent":0,"menu_order":40,"comment_status":"closed","ping_status":"open","template":"","meta":{"footnotes":""},"class_list":{"0":"post-696","1":"page","2":"type-page","3":"status-publish","4":"has-post-thumbnail","6":"page_category-math-advertising-group","7":"page_category-systems-of-equations-and-their-solutions-videos","8":"page_type-video","9":"content_type-practice-questions","10":"subject_matter-math"},"aioseo_notices":[],"_links":{"self":[{"href":"https:\/\/www.mometrix.com\/academy\/wp-json\/wp\/v2\/pages\/696","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.mometrix.com\/academy\/wp-json\/wp\/v2\/pages"}],"about":[{"href":"https:\/\/www.mometrix.com\/academy\/wp-json\/wp\/v2\/types\/page"}],"author":[{"embeddable":true,"href":"https:\/\/www.mometrix.com\/academy\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.mometrix.com\/academy\/wp-json\/wp\/v2\/comments?post=696"}],"version-history":[{"count":6,"href":"https:\/\/www.mometrix.com\/academy\/wp-json\/wp\/v2\/pages\/696\/revisions"}],"predecessor-version":[{"id":279250,"href":"https:\/\/www.mometrix.com\/academy\/wp-json\/wp\/v2\/pages\/696\/revisions\/279250"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/www.mometrix.com\/academy\/wp-json\/wp\/v2\/media\/187040"}],"wp:attachment":[{"href":"https:\/\/www.mometrix.com\/academy\/wp-json\/wp\/v2\/media?parent=696"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}