{"id":37252,"date":"2018-01-12T16:49:18","date_gmt":"2018-01-12T16:49:18","guid":{"rendered":"https:\/\/www.mometrix.com\/academy\/?page_id=37252"},"modified":"2026-10-22T17:33:43","modified_gmt":"2026-10-22T22:33:43","slug":"finding-the-slope-of-a-line","status":"publish","type":"page","link":"https:\/\/www.mometrix.com\/academy\/finding-the-slope-of-a-line\/","title":{"rendered":"Finding the Slope of a Line"},"content":{"rendered":"\n\t\t\t<div id=\"mmDeferVideoEncompass_b-VeMBRYGZ0\" style=\"position: relative;\">\n\t\t\t<picture>\n\t\t\t\t<source srcset=\"https:\/\/www.mometrix.com\/academy\/wp-content\/uploads\/2023\/01\/circle-play-duotone.webp\" type=\"image\/webp\">\n\t\t\t\t<source srcset=\"https:\/\/www.mometrix.com\/academy\/wp-content\/uploads\/2023\/01\/circle-play-duotone.png\" type=\"image\/png\">\n\t\t\t\t<img fetchpriority=\"high\" decoding=\"async\" loading=\"eager\" id=\"videoThumbnailImage_b-VeMBRYGZ0\" data-source-video-id=\"b-VeMBRYGZ0\" src=\"https:\/\/www.mometrix.com\/academy\/wp-content\/uploads\/2023\/01\/circle-play-duotone.png\" alt=\"Finding the Slope of a Line Video\" height=\"464\" width=\"825\" class=\"size-full\" data-matomo-title=\"Finding the Slope of a Line\" style=\"background-size:contain;background-image:url(&quot;https:\/\/www.mometrix.com\/academy\/wp-content\/uploads\/2023\/02\/178-finding-the-slope-1.webp&quot;);\">\n\t\t\t<\/picture>\n\t\t\t<\/div>\n\t\t\t<style>#videoThumbnailImage_b-VeMBRYGZ0:hover {cursor:pointer;}<\/style>\n\t\t\t<script defer>\n\t\t\t(function (config) {\n\t\t\t\t\"use strict\";\n\t\t\t\tvar thumbnail = document.getElementById(config.thumbnailId);\n\t\t\t\tvar container = document.getElementById(config.containerId);\n\t\t\t\tif (!thumbnail || !container) { return; }\n\n\t\t\t\tthumbnail.addEventListener(\"click\", function () {\n\t\t\t\t\tvar videoId = thumbnail.getAttribute(\"data-source-video-id\");\n\t\t\t\t\tif (!\/^[A-Za-z0-9_-]{11}$\/.test(videoId)) { return; }\n\n\t\t\t\t\tvar iframe = document.createElement(\"iframe\");\n\t\t\t\t\tiframe.id = \"yt\" + videoId;\n\t\t\t\t\tiframe.src = \"https:\/\/www.youtube-nocookie.com\/embed\/\" + videoId + \"?autoplay=1&controls=1&wmode=opaque&rel=0&egm=0&iv_load_policy=3&hd=0&enablejsapi=1\";\n\t\t\t\t\tiframe.frameBorder = \"0\";\n\t\t\t\t\tiframe.allow = \"autoplay; fullscreen\";\n\t\t\t\t\tiframe.width = thumbnail.width;\n\t\t\t\t\tiframe.height = thumbnail.height;\n\t\t\t\t\tiframe.setAttribute(\"data-matomo-title\", config.pageTitle);\n\n\t\t\t\t\tvar help = document.createElement(\"div\");\n\t\t\t\t\thelp.id = config.messageId;\n\t\t\t\t\thelp.style.cssText = \"display:none;position:absolute;top:-24px;width:100%;text-align:center;\";\n\t\t\t\t\tvar helpText = document.createElement(\"span\");\n\t\t\t\t\thelpText.style.cssText = \"font-style:italic;font-size:small;border-top:1px solid #fc0;\";\n\t\t\t\t\thelpText.appendChild(document.createTextNode(\"Having trouble? \"));\n\t\t\t\t\tvar helpLink = document.createElement(\"a\");\n\t\t\t\t\thelpLink.href = \"https:\/\/www.youtube.com\/watch?v=\" + encodeURIComponent(videoId);\n\t\t\t\t\thelpLink.target = \"_blank\";\n\t\t\t\t\thelpLink.rel = \"noopener noreferrer\";\n\t\t\t\t\thelpLink.textContent = \"Click here to watch on YouTube.\";\n\t\t\t\t\thelpText.appendChild(helpLink);\n\t\t\t\t\thelp.appendChild(helpText);\n\n\t\t\t\t\tcontainer.replaceChildren(iframe);\n\t\t\t\t\tcontainer.prepend(help);\n\t\t\t\t\tsetTimeout(function () { help.style.display = \"block\"; }, 2000);\n\t\t\t\t});\n\t\t\t})({\"containerId\":\"mmDeferVideoEncompass_b-VeMBRYGZ0\",\"thumbnailId\":\"videoThumbnailImage_b-VeMBRYGZ0\",\"messageId\":\"mmDeferVideoYTMessage_b-VeMBRYGZ0\",\"pageTitle\":\"Finding the Slope of a Line\"});\n\t\t\t<\/script>\n\t\t\n<div class=\"moc-toc hide-on-desktop hide-on-tablet\">\n<div class=\"moc-toc-header\"><button type=\"button\" class=\"moc-toc-toggle\" aria-controls=\"moc-toc-37252-2\" aria-expanded=\"false\"><span class=\"screen-reader-text\">Toggle table of contents<\/span><span aria-hidden=\"true\" class=\"moc-toc-toggle-icon\">\u2304<\/span><\/button><\/p>\n<p>On this page<\/p>\n<\/div>\n<nav id=\"moc-toc-37252-2\" aria-label=\"Table of contents\" hidden>\n<ul>\n<li class=\"toc-h2\"><a class=\"smooth-scroll\" href=\"#Reviewing_the_Basics\">Reviewing the Basics<\/a><\/li>\n<li class=\"toc-h2\"><a class=\"smooth-scroll\" href=\"#Finding_the_Slope_of_a_Line\">Finding the Slope of a Line<\/a><\/li>\n<li class=\"toc-h3\"><a class=\"smooth-scroll\" href=\"#Example_1\">Example #1<\/a><\/li>\n<li class=\"toc-h3\"><a class=\"smooth-scroll\" href=\"#Example_2\">Example #2<\/a><\/li>\n<li class=\"toc-h2\"><a class=\"smooth-scroll\" href=\"#Slope_of_a_Line_Practice_Questions\">Slope of a Line Practice Questions<\/a><\/li>\n<\/ul>\n<\/nav>\n<\/div>\n<div class=\"accordion\"><input id=\"transcript\" type=\"checkbox\" class=\"spoiler_button\" \/><label for=\"transcript\">Transcript<\/label><input id=\"PQs\" type=\"checkbox\" class=\"spoiler_button\" \/><label for=\"PQs\">Practice<\/label><a href=\"https:\/\/www.mometrix.com\/academy\/slope-calculator\/\" target=\"_self\" style=\"margin: 0 auto;\"><span class=\"accordion_calculator_button\">Calculator<\/span><\/a><\/p>\n<div class=\"spoiler\" id=\"transcript-spoiler\">\n<p>Hey, guys! Welcome to this video on finding the slope!<\/p>\n<h2><span id=\"Reviewing_the_Basics\" class=\"m-toc-anchor\"><\/span>Reviewing the Basics<\/h2>\n<p>So, I\u2019m assuming that you already know how to find the slope of a <a class=\"ylist\" href=\"https:\/\/www.mometrix.com\/academy\/slope-intercept-and-point-slope-forms\/\">line<\/a> when given the equation of a line.<\/p>\n<p>We know that the standard form for the equation of a line is \\(y=mx + b\\), where \\(m\\) is our slope and \\(b\\) is our \\(y\\)-intercept.<\/p>\n<p>We also know that slope is rise over run, or \\(y\\) over \\(x\\).<\/p>\n<div class=\"examplesentence\">\\(\\text{slope}=\\) <span style=\"font-size:120%\">\\(\\frac{\\text{rise}}{\\text{run}}\\)<\/span><span style=\"font-size:100%\"> \\( = \\) <\/span><span style=\"font-size:120%\">\\(\\frac{y}{x}\\)<\/span><\/div>\n<p>&nbsp;<br \/>\nBut now, how do we find the slope of a line when only given two points on a graph?<\/p>\n<p>Let\u2019s take a look. <\/p>\n<h2><span id=\"Finding_the_Slope_of_a_Line\" class=\"m-toc-anchor\"><\/span>Finding the Slope of a Line<\/h2>\n<h3><span id=\"Example_1\" class=\"m-toc-anchor\"><\/span>Example #1<\/h3>\n<p>So, we have our <a class=\"ylist\" href=\"https:\/\/www.mometrix.com\/academy\/cartesian-coordinate-plane-and-graphing\/\">graph<\/a>.<\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/www.mometrix.com\/academy\/wp-content\/uploads\/2021\/09\/graph-two-points.png\" alt=\"A graph with a line connecting the points (1,3) and (3,7)\" width=\"496\" height=\"639\" class=\"aligncenter size-full wp-image-91954\" style=\"box-shadow: 1.5px 1.5px 3px grey\" srcset=\"https:\/\/www.mometrix.com\/academy\/wp-content\/uploads\/2021\/09\/graph-two-points.png 496w, https:\/\/www.mometrix.com\/academy\/wp-content\/uploads\/2021\/09\/graph-two-points-233x300.png 233w\" sizes=\"auto, (max-width: 496px) 100vw, 496px\" \/><\/p>\n<p>So, we have two points on our line \\((1,3)\\) and \\((3,7)\\), but how do we find the slope of the line?<\/p>\n<p>Well, we can do this by dividing the difference of the \\(y\\)-coordinates of the two points you\u2019ve been given by the difference of the \\(x\\)-coordinates from the same set of points.<\/p>\n<p>Let me just write out, mathematically, everything that I just said.<\/p>\n<p>So, we find the slope by dividing by the difference between our \\(y\\)-coordinates. That can be written like this: \\(\\frac{y_{2}-y_{1}}{x_{2}-x_{1}}=\\text{slope}\\)<\/p>\n<p>Now, you just need to plug in your \\(y\\)-values and your \\(x\\)-values.<\/p>\n<h3><span id=\"Example_2\" class=\"m-toc-anchor\"><\/span>Example #2<\/h3>\n<p>But here&#8217;s another very important thing that many students get confused about, and it\u2019s a great question: Which set of coordinates are my \\(x_{1}\\) and \\(y_{1}\\), and which set of coordinates are my \\(x_{2}\\) and \\(y_{2}\\)?<\/p>\n<p>The answer is: It doesn\u2019t matter.<\/p>\n<p>However, what you can\u2019t do is assign \\(x_{1}\\) to the \\(x\\)-value in a set of coordinates, and \\(y_{2}\\) to the corresponding \\(y\\)-values. For example, in our points on the graph above, I couldn\u2019t say that the 1 is my \\(x_{1}\\) and then the 3 is my \\(y_{2}\\). If I make 1 \\(x_{1}\\), then my corresponding \\(y\\)-value here has to be \\(y_{1}\\). What doesn\u2019t matter is whether or not I make this set of points my \\((x_{1},y_{1})\\), or this set of points my \\((x_{1},y_{1})\\).<\/p>\n<p>So now, let\u2019s pick whichever point we want to be our \\((x_{1},y_{1})\\) and for this video I\u2019ll just say that \\((1,3)\\) will be our \\((x_{1},y_{1})\\), which makes \\((3,7)\\) our \\((x_{2},y_{2})\\).<\/p>\n<p>Now, let&#8217;s plug in our values:<\/p>\n<p>Since 7 is our \\(y_{2}\\), we have \\(7-y_{1}\\), and our \\(y_{1}\\) is equal to 3. So, \\(7-3\\). Over the difference between our \\(x\\)-values, \\(x_{2}\\), which is 3 minus \\(x_{1}\\), which is 1.<\/p>\n<p>So we have \\(\\frac{7-3}{3-1}\\). That&#8217;s gonna give us \\(\\frac{4}{2}\\), which reduces to be \\(\\frac{2}{1}\\), which is the same thing as 2.<\/p>\n<p>Just to show you guys it doesn\u2019t matter which set of points you make your \\((x_{1},y_{1})\\), and \\((x_{2},y_{2})\\), I\u2019ll switch them around.<\/p>\n<p>So let\u2019s make \\((1,3)\\) \\((x_{2},y_{2})\\) and \\((3,7)\\) \\((x_{1},y_{1})\\).<\/p>\n<p>When we plug them in we get \\(\\frac{3-7}{1-3}=\\frac{-4}{-2}\\). When we have a negative divided by a negative you get a positive, so this simply reduces to \\(\\frac{2}{1}\\), or 2.<\/p>\n<p>So, we see that our two answers are the same, and that it does not matter which set of coordinates we assign to be our \\((x_{1},y_{1})\\), and \\((x_{2},y_{2})\\).<\/p>\n<p>I hope this video has been helpful to you!<\/p>\n<p>See you next time!<\/p>\n<\/div>\n<div class=\"spoiler\" id=\"PQs-spoiler\">\n<h2 style=\"text-align:center\"><span id=\"Slope_of_a_Line_Practice_Questions\" class=\"m-toc-anchor\" aria-hidden=\"true\"><\/span>Slope of a Line Practice Questions<\/h2>\n\n\t\t\t\t<div class=\"PQ\">\n\t\t\t\t\t<strong>Question #1:<\/strong>\n\t\t\t\t\t<div style=\"margin-left:10px;\"><p>&nbsp;<br \/>\nIn the standard equation of a line, what do the variables \\(m\\) and \\(b\\) represent in \\(y=mx+b\\)?<\/p>\n<\/div>\n\t\t\t\t\t<div class=\"PQ-Choices\"><div class=\"PQ\"  id=\"PQ-1-1\">\\(m\\) represents \\(y\\)-intercept and \\(b\\) represents the slope<\/div><div class=\"PQ\"  id=\"PQ-1-2\">\\(m\\) represents slope and \\(b\\) represents the \\(x\\)-intercept<\/div><div class=\"PQ correct_answer\"  id=\"PQ-1-3\">\\(m\\) represents slope and \\(b\\) represents the \\(y\\)-intercept<\/div><div class=\"PQ\"  id=\"PQ-1-4\">\\(m\\) represents \\(x\\)-intercept and \\(b\\) represents the slope<\/div>\n\t\t\t\t\t<\/div>\n\t\t\t\t\t<input id=\"PQ-1\" type=\"checkbox\" class=\"spoiler_button\" \/><label for=\"PQ-1\" style=\"width: 150px;\">Show Answer<\/label>\n\t\t\t\t\t<div class=\"answer\" id=\"PQ-1-spoiler\">\n\t\t\t\t\t\t<strong>Answer:<\/strong><div style=\"margin-left:10px;\"><p>In the equation \\(y=mx+b\\), \\(x\\) and \\(y\\) represent a coordinate pair \\((x, y)\\) that is located on the line of the equation. The variable \\(m\\) represents the slope of the line, and \\(b\\) represents the \\(y\\)-intercept, or where the line crosses through the \\(y\\)-axis.<\/p>\n<\/div>\n\t\t\t\t\t\t<input id=\"PQ-1-hide\" type=\"checkbox\" class=\"spoiler_button\" \/><label for=\"PQ-1-hide\" style=\"width: 150px;\">Hide Answer<\/label>\n\t\t\t\t\t<\/div>\n\t\t\t\t<\/div>\n\t\t\t\t<div class=\"PQ\">\n\t\t\t\t\t<strong>Question #2:<\/strong>\n\t\t\t\t\t<div style=\"margin-left:10px;\"><p>&nbsp;<br \/>\nWhat is the slope of the line below?<\/p>\n<p><img decoding=\"async\" src=\"https:\/\/www.mometrix.com\/academy\/wp-content\/uploads\/2025\/10\/Slop-graph-example-1.svg\" alt=\"A graph with a straight line passing through the points (1, 3) and (3, 7) on the xy-plane. The x- and y-axes are labeled and marked in increments of 5.\" width=\"298.35\" height=\"257.85\" class=\"aligncenter size-full wp-image-274141\" role=\"img\" \/><\/p>\n<\/div>\n\t\t\t\t\t<div class=\"PQ-Choices\"><div class=\"PQ\"  id=\"PQ-2-1\"><span style=\"font-size: 120%\">\\(\\frac{1}{2}\\)<\/span><\/div><div class=\"PQ\"  id=\"PQ-2-2\">1<\/div><div class=\"PQ correct_answer\"  id=\"PQ-2-3\">2<\/div><div class=\"PQ\"  id=\"PQ-2-4\">3<\/div>\n\t\t\t\t\t<\/div>\n\t\t\t\t\t<input id=\"PQ-2\" type=\"checkbox\" class=\"spoiler_button\" \/><label for=\"PQ-2\" style=\"width: 150px;\">Show Answer<\/label>\n\t\t\t\t\t<div class=\"answer\" id=\"PQ-2-spoiler\">\n\t\t\t\t\t\t<strong>Answer:<\/strong><div style=\"margin-left:10px;\"><p>The slope of the graphed line can be found by using the two plotted points \\((1,3)\\) and \\((3,7)\\). The slope can be calculated by dividing the difference of the \\(y\\)-coordinates by the difference of the \\(x\\)-coordinates.<\/p>\n<p>Plug in the \\(x\\)&#8211; and \\(y\\)-coordinates:<\/p>\n<p style=\"text-align: center\">\\(3-7=-4\\)<br \/>\n\\(1-3=-2\\)<\/p>\n<p style=\"text-align: center\"><span style=\"font-size: 120%\">\\(\\frac{-4}{-2}\\)<\/span>\\(\\:=2\\)<\/p>\n<p>Therefore, the slope of the line is 2.<\/p>\n<\/div>\n\t\t\t\t\t\t<input id=\"PQ-2-hide\" type=\"checkbox\" class=\"spoiler_button\" \/><label for=\"PQ-2-hide\" style=\"width: 150px;\">Hide Answer<\/label>\n\t\t\t\t\t<\/div>\n\t\t\t\t<\/div>\n\t\t\t\t<div class=\"PQ\">\n\t\t\t\t\t<strong>Question #3:<\/strong>\n\t\t\t\t\t<div style=\"margin-left:10px;\"><p>&nbsp;<br \/>\nWhat is the slope of the line below?<\/p>\n<p><img decoding=\"async\" src=\"https:\/\/www.mometrix.com\/academy\/wp-content\/uploads\/2025\/10\/Slop-graph-example-2.svg\" alt=\"A straight line passes through points (1, 4) and (2, 2) on a Cartesian coordinate grid with labeled axes.\" width=\"298.35\" height=\"257.85\" class=\"aligncenter size-full wp-image-274144\" role=\"img\" \/><\/p>\n<\/div>\n\t\t\t\t\t<div class=\"PQ-Choices\"><div class=\"PQ correct_answer\"  id=\"PQ-3-1\">\u22122<\/div><div class=\"PQ\"  id=\"PQ-3-2\">2<\/div><div class=\"PQ\"  id=\"PQ-3-3\">\u22124<\/div><div class=\"PQ\"  id=\"PQ-3-4\">4<\/div>\n\t\t\t\t\t<\/div>\n\t\t\t\t\t<input id=\"PQ-3\" type=\"checkbox\" class=\"spoiler_button\" \/><label for=\"PQ-3\" style=\"width: 150px;\">Show Answer<\/label>\n\t\t\t\t\t<div class=\"answer\" id=\"PQ-3-spoiler\">\n\t\t\t\t\t\t<strong>Answer:<\/strong><div style=\"margin-left:10px;\"><p>Calculate the slope by dividing the difference of the \\(y\\)-coordinates by the difference of the \\(x\\)-coordinates.<\/p>\n<p>Plug in the \\(x\\)&#8211; and \\(y\\)-coordinates:<\/p>\n<p style=\"text-align: center\">\\(4-2=2\\)<br \/>\n\\(1-2=-1\\)<\/p>\n<p style=\"text-align: center\"><span style=\"font-size: 120%\">\\(\\frac{2}{-1}\\)<\/span>\\(\\:=-2\\)<\/p>\n<p>Therefore, the slope of the line is \u22122.<\/p>\n<\/div>\n\t\t\t\t\t\t<input id=\"PQ-3-hide\" type=\"checkbox\" class=\"spoiler_button\" \/><label for=\"PQ-3-hide\" style=\"width: 150px;\">Hide Answer<\/label>\n\t\t\t\t\t<\/div>\n\t\t\t\t<\/div>\n\t\t\t\t<div class=\"PQ\">\n\t\t\t\t\t<strong>Question #4:<\/strong>\n\t\t\t\t\t<div style=\"margin-left:10px;\"><p>&nbsp;<br \/>\nWhat is the slope of the line below?<\/p>\n<p><img decoding=\"async\" src=\"https:\/\/www.mometrix.com\/academy\/wp-content\/uploads\/2025\/10\/Slop-graph-example-3.svg\" alt=\"A graph with a straight line passing through the points (0,1) and (2,2) on an x-y coordinate plane.\" width=\"298.35\" height=\"257.85\" class=\"aligncenter size-full wp-image-274147\" role=\"img\" \/><\/p>\n<\/div>\n\t\t\t\t\t<div class=\"PQ-Choices\"><div class=\"PQ\"  id=\"PQ-4-1\"><span style=\"font-size: 120%\">\\(\\frac{1}{4}\\)<\/span><\/div><div class=\"PQ correct_answer\"  id=\"PQ-4-2\"><span style=\"font-size: 120%\">\\(\\frac{1}{2}\\)<\/span><\/div><div class=\"PQ\"  id=\"PQ-4-3\">2<\/div><div class=\"PQ\"  id=\"PQ-4-4\">4<\/div>\n\t\t\t\t\t<\/div>\n\t\t\t\t\t<input id=\"PQ-4\" type=\"checkbox\" class=\"spoiler_button\" \/><label for=\"PQ-4\" style=\"width: 150px;\">Show Answer<\/label>\n\t\t\t\t\t<div class=\"answer\" id=\"PQ-4-spoiler\">\n\t\t\t\t\t\t<strong>Answer:<\/strong><div style=\"margin-left:10px;\"><p>The slope of the graphed line can be found using the two plotted points \\((0,1)\\) and \\((2,2)\\). The slope can be calculated by dividing the difference of the \\(y\\)-coordinates by the difference of the \\(x\\)-coordinates.<\/p>\n<p>Plug in the \\(x\\)&#8211; and \\(y\\)-coordinates:<\/p>\n<p style=\"text-align: center\">\\(1-2=-1\\)<br \/>\n\\(0-2=-2\\)<\/p>\n<p style=\"text-align: center;font-size: 120%\">\\(\\frac{-1}{-2}=\\frac{1}{2}\\)<\/p>\n<p>Therefore, the slope of the line is <span style=\"font-size: 120%\">\\(\\frac{1}{2}\\)<\/span>.<\/p>\n<\/div>\n\t\t\t\t\t\t<input id=\"PQ-4-hide\" type=\"checkbox\" class=\"spoiler_button\" \/><label for=\"PQ-4-hide\" style=\"width: 150px;\">Hide Answer<\/label>\n\t\t\t\t\t<\/div>\n\t\t\t\t<\/div>\n\t\t\t\t<div class=\"PQ\">\n\t\t\t\t\t<strong>Question #5:<\/strong>\n\t\t\t\t\t<div style=\"margin-left:10px;\"><p>&nbsp;<br \/>\nWhat is the slope of the line below?<\/p>\n<p><img decoding=\"async\" src=\"https:\/\/www.mometrix.com\/academy\/wp-content\/uploads\/2025\/10\/Slop-graph-example-4.svg\" alt=\"A graph with a line passing through points (0,0) and (6,4) on the Cartesian plane, labeled axes x and y, and gridlines marked in units of five.\" width=\"298.35\" height=\"257.85\" class=\"aligncenter size-full wp-image-274150\" role=\"img\" \/><\/p>\n<\/div>\n\t\t\t\t\t<div class=\"PQ-Choices\"><div class=\"PQ\"  id=\"PQ-5-1\">2<\/div><div class=\"PQ\"  id=\"PQ-5-2\">3<\/div><div class=\"PQ\"  id=\"PQ-5-3\"><span style=\"font-size: 120%\">\\(\\frac{3}{2}\\)<\/span><\/div><div class=\"PQ correct_answer\"  id=\"PQ-5-4\"><span style=\"font-size: 120%\">\\(\\frac{2}{3}\\)<\/span><\/div>\n\t\t\t\t\t<\/div>\n\t\t\t\t\t<input id=\"PQ-5\" type=\"checkbox\" class=\"spoiler_button\" \/><label for=\"PQ-5\" style=\"width: 150px;\">Show Answer<\/label>\n\t\t\t\t\t<div class=\"answer\" id=\"PQ-5-spoiler\">\n\t\t\t\t\t\t<strong>Answer:<\/strong><div style=\"margin-left:10px;\"><p>The slope of the graphed line can be found using the two plotted points \\((0,0)\\) and \\((6,4)\\). The slope can be calculated by dividing the difference of the \\(y\\)-coordinates by the difference of the \\(x\\)-coordinates.<\/p>\n<p>Plug in the \\(x\\)&#8211; and \\(y\\)-coordinates:<\/p>\n<p style=\"text-align: center\">\\(0-4=-4\\)<br \/>\n\\(0-6=-6\\)<\/p>\n<p style=\"text-align: center;font-size: 120%\">\\(\\frac{-4}{-6}=\\frac{4}{6}=\\frac{2}{3}\\)<\/p>\n<p>Therefore, the slope of the line is <span style=\"font-size: 120%\">\\(\\frac{2}{3}\\)<\/span>.<\/p>\n<\/div>\n\t\t\t\t\t\t<input id=\"PQ-5-hide\" type=\"checkbox\" class=\"spoiler_button\" \/><label for=\"PQ-5-hide\" style=\"width: 150px;\">Hide Answer<\/label>\n\t\t\t\t\t<\/div>\n\t\t\t\t<\/div><\/div>\n<\/div>\n\n<div class=\"home-buttons\">\n<p><a href=\"https:\/\/www.mometrix.com\/academy\/algebra-i\/\">Return to Algebra I Videos<\/a><\/p>\n<\/div>\n","protected":false},"excerpt":{"rendered":"<p>Return to Algebra I Videos<\/p>\n","protected":false},"author":1,"featured_media":91216,"parent":0,"menu_order":0,"comment_status":"closed","ping_status":"closed","template":"","meta":{"_acf_changed":false,"footnotes":""},"class_list":{"0":"post-37252","1":"page","2":"type-page","3":"status-publish","4":"has-post-thumbnail","6":"page_category-algebra-1-pages","7":"page_category-course-pages","8":"page_category-linear-equations-videos","9":"page_category-math-advertising-group","10":"page_type-video","11":"content_type-practice-questions","12":"subject_matter-math"},"acf":[],"aioseo_notices":[],"aioseo_head":"\n\t\t<!-- All in One SEO Pro 5.0.4 - aioseo.com -->\n\t<meta name=\"description\" content=\"In math, a slope is the rise (y-values) divided by the run (x-values). 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