{"id":37252,"date":"2018-01-12T16:49:18","date_gmt":"2018-01-12T16:49:18","guid":{"rendered":"https:\/\/www.mometrix.com\/academy\/?page_id=37252"},"modified":"2026-03-25T11:00:58","modified_gmt":"2026-03-25T16:00:58","slug":"finding-the-slope-of-a-line","status":"publish","type":"page","link":"https:\/\/www.mometrix.com\/academy\/finding-the-slope-of-a-line\/","title":{"rendered":"Finding the Slope of a Line"},"content":{"rendered":"\n\t\t\t<div id=\"mmDeferVideoEncompass_b-VeMBRYGZ0\" style=\"position: relative;\">\n\t\t\t<picture>\n\t\t\t\t<source srcset=\"https:\/\/www.mometrix.com\/academy\/wp-content\/uploads\/2023\/01\/circle-play-duotone.webp\" type=\"image\/webp\">\n\t\t\t\t<source srcset=\"https:\/\/www.mometrix.com\/academy\/wp-content\/uploads\/2023\/01\/circle-play-duotone.png\" type=\"image\/jpeg\"> \n\t\t\t\t<img fetchpriority=\"high\" decoding=\"async\" loading=\"eager\" id=\"videoThumbnailImage_b-VeMBRYGZ0\" data-source-videoID=\"b-VeMBRYGZ0\" src=\"https:\/\/www.mometrix.com\/academy\/wp-content\/uploads\/2023\/01\/circle-play-duotone.png\" alt=\"Finding the Slope of a Line Video\" height=\"464\" width=\"825\" class=\"size-full\" data-matomo-title = \"Finding the Slope of a Line\">\n\t\t\t<\/picture>\n\t\t\t<\/div>\n\t\t\t<style>img#videoThumbnailImage_b-VeMBRYGZ0:hover {cursor:pointer;} img#videoThumbnailImage_b-VeMBRYGZ0 {background-size:contain;background-image:url(\"https:\/\/www.mometrix.com\/academy\/wp-content\/uploads\/2023\/02\/178-finding-the-slope-1.webp\");}<\/style>\n\t\t\t<script defer>\n\t\t\t  jQuery(\"img#videoThumbnailImage_b-VeMBRYGZ0\").click(function() {\n\t\t\t\tlet videoId = jQuery(this).attr(\"data-source-videoID\");\n\t\t\t\tlet helpTag = '<div id=\"mmDeferVideoYTMessage_b-VeMBRYGZ0\" style=\"display: none;position: absolute;top: -24px;width: 100%;text-align: center;\"><span style=\"font-style: italic;font-size: small;border-top: 1px solid #fc0;\">Having trouble? <a href=\"https:\/\/www.youtube.com\/watch?v='+videoId+'\" target=\"_blank\">Click here to watch on YouTube.<\/a><\/span><\/div>';\n\t\t\t\tlet tag = document.createElement(\"iframe\");\n\t\t\t\ttag.id = \"yt\" + videoId;\n\t\t\t\ttag.src = \"https:\/\/www.youtube-nocookie.com\/embed\/\" + videoId + \"?autoplay=1&controls=1&wmode=opaque&rel=0&egm=0&iv_load_policy=3&hd=0&enablejsapi=1\";\n\t\t\t\ttag.frameborder = 0;\n\t\t\t\ttag.allow = \"autoplay; fullscreen\";\n\t\t\t\ttag.width = this.width;\n\t\t\t\ttag.height = this.height;\n\t\t\t\ttag.setAttribute(\"data-matomo-title\",\"Finding the Slope of a Line\");\n\t\t\t\tjQuery(\"div#mmDeferVideoEncompass_b-VeMBRYGZ0\").html(tag);\n\t\t\t\tjQuery(\"div#mmDeferVideoEncompass_b-VeMBRYGZ0\").prepend(helpTag);\n\t\t\t\tsetTimeout(function(){jQuery(\"div#mmDeferVideoYTMessage_b-VeMBRYGZ0\").css(\"display\", \"block\");}, 2000);\n\t\t\t  });\n\t\t\t  \n\t\t\t<\/script>\n\t\t\n<p><script>\nfunction 4z0_Function() {\n  var x = document.getElementById(\"4z0\");\n  if (x.style.display === \"none\") {\n    x.style.display = \"block\";\n  } else {\n    x.style.display = \"none\";\n  }\n}\n<\/script><\/p>\n<div class=\"moc-toc hide-on-desktop hide-on-tablet\">\n<div><button onclick=\"4z0_Function()\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/www.mometrix.com\/academy\/wp-content\/uploads\/2024\/12\/toc2.svg\" width=\"16\" height=\"16\" alt=\"show or hide table of contents\"><\/button><\/p>\n<p>On this page<\/p>\n<\/div>\n<nav id=\"4z0\" style=\"display:none;\">\n<ul>\n<li class=\"toc-h2\"><a href=\"#Reviewing_the_Basics\" class=\"smooth-scroll\">Reviewing the Basics<\/a><\/li>\n<li class=\"toc-h2\"><a href=\"#Finding_the_Slope_of_a_Line\" class=\"smooth-scroll\">Finding the Slope of a Line<\/a>\n<ul><\/li>\n<li class=\"toc-h3\"><a href=\"#Example_1\" class=\"smooth-scroll\">Example #1<\/a><\/li>\n<li class=\"toc-h3\"><a href=\"#Example_2\" class=\"smooth-scroll\">Example #2<\/a><\/li>\n<\/ul>\n<\/li>\n<li class=\"toc-h2\"><a href=\"#Slope_of_a_Line_Practice_Questions\" class=\"smooth-scroll\">Slope of a Line Practice Questions<\/a><\/li>\n<\/ul>\n<\/nav>\n<\/div>\n<div class=\"accordion\"><input id=\"transcript\" type=\"checkbox\" class=\"spoiler_button\" \/><label for=\"transcript\">Transcript<\/label><input id=\"PQs\" type=\"checkbox\" class=\"spoiler_button\" \/><label for=\"PQs\">Practice<\/label><a href=\"https:\/\/www.mometrix.com\/academy\/slope-calculator\/\" target=\"none\" style=\"margin: 0 auto;\"><span class=\"accordion_calculator_button\">Calculator<\/span><\/a><\/p>\n<div class=\"spoiler\" id=\"transcript-spoiler\">\n<p>Hey, guys! Welcome to this video on finding the slope!<\/p>\n<h2><span id=\"Reviewing_the_Basics\" class=\"m-toc-anchor\"><\/span>Reviewing the Basics<\/h2>\n<p>\nSo, I\u2019m assuming that you already know how to find the slope of a <a class=\"ylist\" href=\"https:\/\/www.mometrix.com\/academy\/slope-intercept-and-point-slope-forms\/\">line<\/a> when given the equation of a line.<\/p>\n<p>We know that the standard form for the equation of a line is \\(y=mx + b\\), where \\(m\\) is our slope and \\(b\\) is our \\(y\\)-intercept.<\/p>\n<p>We also know that slope is rise over run, or \\(y\\) over \\(x\\).<\/p>\n<div class=\"examplesentence\">\\(\\text{slope}=\\) <span style=\"font-size:120%\">\\(\\frac{\\text{rise}}{\\text{run}}\\)<\/span><span style=\"font-size:100%\"> \\( = \\) <\/span><span style=\"font-size:120%\">\\(\\frac{y}{x}\\)<\/span><\/div>\n<p>\n&nbsp;<br \/>\nBut now, how do we find the slope of a line when only given two points on a graph?<\/p>\n<p>Let\u2019s take a look. <\/p>\n<h2><span id=\"Finding_the_Slope_of_a_Line\" class=\"m-toc-anchor\"><\/span>Finding the Slope of a Line<\/h2>\n<h3><span id=\"Example_1\" class=\"m-toc-anchor\"><\/span>Example #1<\/h3>\n<p>\nSo, we have our <a class=\"ylist\" href=\"https:\/\/www.mometrix.com\/academy\/cartesian-coordinate-plane-and-graphing\/\">graph<\/a>.<\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/www.mometrix.com\/academy\/wp-content\/uploads\/2021\/09\/graph-two-points.png\" alt=\"A graph with a line connecting the points (1,3) and (3,7)\" width=\"496\" height=\"639\" class=\"aligncenter size-full wp-image-91954\" style=\"box-shadow: 1.5px 1.5px 3px grey\" srcset=\"https:\/\/www.mometrix.com\/academy\/wp-content\/uploads\/2021\/09\/graph-two-points.png 496w, https:\/\/www.mometrix.com\/academy\/wp-content\/uploads\/2021\/09\/graph-two-points-233x300.png 233w\" sizes=\"auto, (max-width: 496px) 100vw, 496px\" \/><\/p>\n<p>So, we have two points on our line \\((1,3)\\) and \\((3,7)\\), but how do we find the slope of the line?<\/p>\n<p>Well, we can do this by dividing the difference of the \\(y\\)-coordinates of the two points you\u2019ve been given by the difference of the \\(x\\)-coordinates from the same set of points.<\/p>\n<p>Let me just write out, mathematically, everything that I just said.<\/p>\n<p>So, we find the slope by dividing by the difference between our \\(y\\)-coordinates. That can be written like this: \\(\\frac{y_{2}-y_{1}}{x_{2}-x_{1}}=\\text{slope}\\)<\/p>\n<p>Now, you just need to plug in your \\(y\\)-values and your \\(x\\)-values.<\/p>\n<h3><span id=\"Example_2\" class=\"m-toc-anchor\"><\/span>Example #2<\/h3>\n<p>\nBut here&#8217;s another very important thing that many students get confused about, and it\u2019s a great question: Which set of coordinates are my \\(x_{1}\\) and \\(y_{1}\\), and which set of coordinates are my \\(x_{2}\\) and \\(y_{2}\\)?<\/p>\n<p>The answer is: It doesn\u2019t matter.<\/p>\n<p>However, what you can\u2019t do is assign \\(x_{1}\\) to the \\(x\\)-value in a set of coordinates, and \\(y_{2}\\) to the corresponding \\(y\\)-values. For example, in our points on the graph above, I couldn\u2019t say that the 1 is my \\(x_{1}\\) and then the 3 is my \\(y_{2}\\). If I make 1 \\(x_{1}\\), then my corresponding \\(y\\)-value here has to be \\(y_{1}\\). What doesn\u2019t matter is whether or not I make this set of points my \\((x_{1},y_{1})\\), or this set of points my \\((x_{1},y_{1})\\).<\/p>\n<p>So now, let\u2019s pick whichever point we want to be our \\((x_{1},y_{1})\\) and for this video I\u2019ll just say that \\((1,3)\\) will be our \\((x_{1},y_{1})\\), which makes \\((3,7)\\) our \\((x_{2},y_{2})\\).<\/p>\n<p>Now, let&#8217;s plug in our values:<\/p>\n<p>Since 7 is our \\(y_{2}\\), we have \\(7-y_{1}\\), and our \\(y_{1}\\) is equal to 3. So, \\(7-3\\). Over the difference between our \\(x\\)-values, \\(x_{2}\\), which is 3 minus \\(x_{1}\\), which is 1.<\/p>\n<p>So we have \\(\\frac{7-3}{3-1}\\). That&#8217;s gonna give us \\(\\frac{4}{2}\\), which reduces to be \\(\\frac{2}{1}\\), which is the same thing as 2.<\/p>\n<p>Just to show you guys it doesn\u2019t matter which set of points you make your \\((x_{1},y_{1})\\), and \\((x_{2},y_{2})\\), I\u2019ll switch them around.<\/p>\n<p>So let\u2019s make \\((1,3)\\) \\((x_{2},y_{2})\\) and \\((3,7)\\) \\((x_{1},y_{1})\\).<\/p>\n<p>When we plug them in we get \\(\\frac{3-7}{1-3}=\\frac{-4}{-2}\\). When we have a negative divided by a negative you get a positive, so this simply reduces to \\(\\frac{2}{1}\\), or 2.<\/p>\n<p>So, we see that our two answers are the same, and that it does not matter which set of coordinates we assign to be our \\((x_{1},y_{1})\\), and \\((x_{2},y_{2})\\).<\/p>\n<p>I hope this video has been helpful to you!<\/p>\n<p>See you next time!<\/p>\n<\/div>\n<div class=\"spoiler\" id=\"PQs-spoiler\">\n<h2 style=\"text-align:center\"><span id=\"Slope_of_a_Line_Practice_Questions\" class=\"m-toc-anchor\"><\/span>Slope of a Line Practice Questions<\/h2>\n\n\t\t\t\t<div class=\"PQ\">\n\t\t\t\t\t<strong>Question #1:<\/strong>\n\t\t\t\t\t<div style=\"margin-left:10px;\"><p>&nbsp;<br \/>\nIn the standard equation of a line, what do the variables \\(m\\) and \\(b\\) represent in \\(y=mx+b\\)?<\/p>\n<\/div>\n\t\t\t\t\t<div class=\"PQ-Choices\"><div class=\"PQ\"  id=\"PQ-1-1\">\\(m\\) represents \\(y\\)-intercept and \\(b\\) represents the slope<\/div><div class=\"PQ\"  id=\"PQ-1-2\">\\(m\\) represents slope and \\(b\\) represents the \\(x\\)-intercept<\/div><div class=\"PQ correct_answer\"  id=\"PQ-1-3\">\\(m\\) represents slope and \\(b\\) represents the \\(y\\)-intercept<\/div><div class=\"PQ\"  id=\"PQ-1-4\">\\(m\\) represents \\(x\\)-intercept and \\(b\\) represents the slope<\/div>\n\t\t\t\t\t<\/div>\n\t\t\t\t\t<input id=\"PQ-1\" type=\"checkbox\" class=\"spoiler_button\" \/><label for=\"PQ-1\" style=\"width: 150px;\">Show Answer<\/label>\n\t\t\t\t\t<div class=\"answer\" id=\"PQ-1-spoiler\">\n\t\t\t\t\t\t<strong>Answer:<\/strong><div style=\"margin-left:10px;\"><p>In the equation \\(y=mx+b\\), \\(x\\) and \\(y\\) represent a coordinate pair \\((x, y)\\) that is located on the line of the equation. The variable \\(m\\) represents the slope of the line, and \\(b\\) represents the \\(y\\)-intercept, or where the line crosses through the \\(y\\)-axis.<\/p>\n<\/div>\n\t\t\t\t\t\t<input id=\"PQ-1-hide\" type=\"checkbox\" class=\"spoiler_button\" \/><label for=\"PQ-1-hide\" style=\"width: 150px;\">Hide Answer<\/label>\n\t\t\t\t\t<\/div>\n\t\t\t\t<\/div>\n\t\t\t\t<div class=\"PQ\">\n\t\t\t\t\t<strong>Question #2:<\/strong>\n\t\t\t\t\t<div style=\"margin-left:10px;\"><p>&nbsp;<br \/>\nWhat is the slope of the line below?<\/p>\n<p><img decoding=\"async\" src=\"https:\/\/www.mometrix.com\/academy\/wp-content\/uploads\/2025\/10\/Slop-graph-example-1.svg\" alt=\"A graph with a straight line passing through the points (1, 3) and (3, 7) on the xy-plane. The x- and y-axes are labeled and marked in increments of 5.\" width=\"298.35\" height=\"257.85\" class=\"aligncenter size-full wp-image-274141\"  role=\"img\" \/><\/p>\n<\/div>\n\t\t\t\t\t<div class=\"PQ-Choices\"><div class=\"PQ\"  id=\"PQ-2-1\"><span style=\"font-size: 120%\">\\(\\frac{1}{2}\\)<\/span><\/div><div class=\"PQ\"  id=\"PQ-2-2\">1<\/div><div class=\"PQ correct_answer\"  id=\"PQ-2-3\">2<\/div><div class=\"PQ\"  id=\"PQ-2-4\">3<\/div>\n\t\t\t\t\t<\/div>\n\t\t\t\t\t<input id=\"PQ-2\" type=\"checkbox\" class=\"spoiler_button\" \/><label for=\"PQ-2\" style=\"width: 150px;\">Show Answer<\/label>\n\t\t\t\t\t<div class=\"answer\" id=\"PQ-2-spoiler\">\n\t\t\t\t\t\t<strong>Answer:<\/strong><div style=\"margin-left:10px;\"><p>The slope of the graphed line can be found by using the two plotted points \\((1, 3)\\) and \\((3, 7)\\). The slope can be calculated by dividing the difference of the \\(y\\)-coordinates by the difference of the \\(x\\)-coordinates.<\/p>\n<p>Plug in the \\(x\\)&#8211; and \\(y\\)-coordinates:<\/p>\n<p style=\"text-align: center\">\\(3-7=-4\\)<br \/>\n\\(1-3=-2\\)<\/p>\n<p style=\"text-align: center;\"><span style=\"font-size: 120%\">\\(\\frac{-4}{-2}\\)<\/span>\\(\\:=2\\)<\/p>\n<p>Therefore, the slope of the line is 2.<\/p>\n<\/div>\n\t\t\t\t\t\t<input id=\"PQ-2-hide\" type=\"checkbox\" class=\"spoiler_button\" \/><label for=\"PQ-2-hide\" style=\"width: 150px;\">Hide Answer<\/label>\n\t\t\t\t\t<\/div>\n\t\t\t\t<\/div>\n\t\t\t\t<div class=\"PQ\">\n\t\t\t\t\t<strong>Question #3:<\/strong>\n\t\t\t\t\t<div style=\"margin-left:10px;\"><p>&nbsp;<br \/>\nWhat is the slope of the line below?<\/p>\n<p><img decoding=\"async\" src=\"https:\/\/www.mometrix.com\/academy\/wp-content\/uploads\/2025\/10\/Slop-graph-example-2.svg\" alt=\"A straight line passes through points (1, 4) and (2, 2) on a Cartesian coordinate grid with labeled axes.\" width=\"298.35\" height=\"257.85\" class=\"aligncenter size-full wp-image-274144\"  role=\"img\" \/><\/p>\n<\/div>\n\t\t\t\t\t<div class=\"PQ-Choices\"><div class=\"PQ correct_answer\"  id=\"PQ-3-1\">\u22122<\/div><div class=\"PQ\"  id=\"PQ-3-2\">2<\/div><div class=\"PQ\"  id=\"PQ-3-3\">\u22124<\/div><div class=\"PQ\"  id=\"PQ-3-4\">4<\/div>\n\t\t\t\t\t<\/div>\n\t\t\t\t\t<input id=\"PQ-3\" type=\"checkbox\" class=\"spoiler_button\" \/><label for=\"PQ-3\" style=\"width: 150px;\">Show Answer<\/label>\n\t\t\t\t\t<div class=\"answer\" id=\"PQ-3-spoiler\">\n\t\t\t\t\t\t<strong>Answer:<\/strong><div style=\"margin-left:10px;\"><p>Calculate the slope by dividing the difference of the \\(y\\)-coordinates by the difference of the \\(x\\)-coordinates.<\/p>\n<p>Plug in the \\(x\\)&#8211; and \\(y\\)-coordinates:<\/p>\n<p style=\"text-align: center\">\\(4-2=2\\)<br \/>\n\\(1-2=-1\\)<\/p>\n<p style=\"text-align: center\"><span style=\"font-size: 120%\">\\(\\frac{2}{-1}\\)<\/span>\\(\\:=-2\\)<\/p>\n<p>Therefore, the slope of the line is \u22122.<\/p>\n<\/div>\n\t\t\t\t\t\t<input id=\"PQ-3-hide\" type=\"checkbox\" class=\"spoiler_button\" \/><label for=\"PQ-3-hide\" style=\"width: 150px;\">Hide Answer<\/label>\n\t\t\t\t\t<\/div>\n\t\t\t\t<\/div>\n\t\t\t\t<div class=\"PQ\">\n\t\t\t\t\t<strong>Question #4:<\/strong>\n\t\t\t\t\t<div style=\"margin-left:10px;\"><p>&nbsp;<br \/>\nWhat is the slope of the line below?<\/p>\n<p><img decoding=\"async\" src=\"https:\/\/www.mometrix.com\/academy\/wp-content\/uploads\/2025\/10\/Slop-graph-example-3.svg\" alt=\"A graph with a straight line passing through the points (0,1) and (2,2) on an x-y coordinate plane.\" width=\"298.35\" height=\"257.85\" class=\"aligncenter size-full wp-image-274147\"  role=\"img\" \/><\/p>\n<\/div>\n\t\t\t\t\t<div class=\"PQ-Choices\"><div class=\"PQ\"  id=\"PQ-4-1\"><span style=\"font-size: 120%\">\\(\\frac{1}{4}\\)<\/span><\/div><div class=\"PQ correct_answer\"  id=\"PQ-4-2\"><span style=\"font-size: 120%\">\\(\\frac{1}{2}\\)<\/span><\/div><div class=\"PQ\"  id=\"PQ-4-3\">2<\/div><div class=\"PQ\"  id=\"PQ-4-4\">4<\/div>\n\t\t\t\t\t<\/div>\n\t\t\t\t\t<input id=\"PQ-4\" type=\"checkbox\" class=\"spoiler_button\" \/><label for=\"PQ-4\" style=\"width: 150px;\">Show Answer<\/label>\n\t\t\t\t\t<div class=\"answer\" id=\"PQ-4-spoiler\">\n\t\t\t\t\t\t<strong>Answer:<\/strong><div style=\"margin-left:10px;\"><p>The slope of the graphed line can be found using the two plotted points \\((0, 1)\\) and \\((2, 2)\\). The slope can be calculated by dividing the difference of the \\(y\\)-coordinates by the difference of the \\(x\\)-coordinates.<\/p>\n<p>Plug in the \\(x\\)&#8211; and \\(y\\)-coordinates:<\/p>\n<p style=\"text-align: center\">\\(1-2=-1\\)<br \/>\n\\(0-2=-2\\)<\/p>\n<p style=\"text-align: center; font-size: 120%\">\\(\\frac{-1}{-2}=\\frac{1}{2}\\)<\/p>\n<p>Therefore, the slope of the line is <span style=\"font-size: 120%\">\\(\\frac{1}{2}\\)<\/span>.<\/p>\n<\/div>\n\t\t\t\t\t\t<input id=\"PQ-4-hide\" type=\"checkbox\" class=\"spoiler_button\" \/><label for=\"PQ-4-hide\" style=\"width: 150px;\">Hide Answer<\/label>\n\t\t\t\t\t<\/div>\n\t\t\t\t<\/div>\n\t\t\t\t<div class=\"PQ\">\n\t\t\t\t\t<strong>Question #5:<\/strong>\n\t\t\t\t\t<div style=\"margin-left:10px;\"><p>&nbsp;<br \/>\nWhat is the slope of the line below?<\/p>\n<p><img decoding=\"async\" src=\"https:\/\/www.mometrix.com\/academy\/wp-content\/uploads\/2025\/10\/Slop-graph-example-4.svg\" alt=\"A graph with a line passing through points (0,0) and (6,4) on the Cartesian plane, labeled axes x and y, and gridlines marked in units of five.\" width=\"298.35\" height=\"257.85\" class=\"aligncenter size-full wp-image-274150\"  role=\"img\" \/><\/p>\n<\/div>\n\t\t\t\t\t<div class=\"PQ-Choices\"><div class=\"PQ\"  id=\"PQ-5-1\">2<\/div><div class=\"PQ\"  id=\"PQ-5-2\">3<\/div><div class=\"PQ\"  id=\"PQ-5-3\"><span style=\"font-size: 120%\">\\(\\frac{3}{2}\\)<\/span><\/div><div class=\"PQ correct_answer\"  id=\"PQ-5-4\"><span style=\"font-size: 120%\">\\(\\frac{2}{3}\\)<\/span><\/div>\n\t\t\t\t\t<\/div>\n\t\t\t\t\t<input id=\"PQ-5\" type=\"checkbox\" class=\"spoiler_button\" \/><label for=\"PQ-5\" style=\"width: 150px;\">Show Answer<\/label>\n\t\t\t\t\t<div class=\"answer\" id=\"PQ-5-spoiler\">\n\t\t\t\t\t\t<strong>Answer:<\/strong><div style=\"margin-left:10px;\"><p>The slope of the graphed line can be found using the two plotted points \\((0,0)\\) and \\((6,4)\\). The slope can be calculated by dividing the difference of the \\(y\\)-coordinates by the difference of the \\(x\\)-coordinates.<\/p>\n<p>Plug in the \\(x\\)&#8211; and \\(y\\)-coordinates:<\/p>\n<p style=\"text-align: center\">\\(0-4=-4\\)<br \/>\n\\(0-6=-6\\)<\/p>\n<p style=\"text-align: center; font-size: 120%\">\\(\\frac{-4}{-6}=\\frac{4}{6}=\\frac{2}{3}\\)<\/p>\n<p>Therefore, the slope of the line is <span style=\"font-size: 120%\">\\(\\frac{2}{3}\\)<\/span>.<\/p>\n<\/div>\n\t\t\t\t\t\t<input id=\"PQ-5-hide\" type=\"checkbox\" class=\"spoiler_button\" \/><label for=\"PQ-5-hide\" style=\"width: 150px;\">Hide Answer<\/label>\n\t\t\t\t\t<\/div>\n\t\t\t\t<\/div><\/div>\n<\/div>\n\n<div class=\"home-buttons\">\n<p><a href=\"https:\/\/www.mometrix.com\/academy\/algebra-i\/\">Return to Algebra I Videos<\/a><\/p>\n<\/div>\n","protected":false},"excerpt":{"rendered":"<p>Return to Algebra I Videos<\/p>\n","protected":false},"author":1,"featured_media":91216,"parent":0,"menu_order":0,"comment_status":"closed","ping_status":"closed","template":"","meta":{"footnotes":""},"class_list":{"0":"post-37252","1":"page","2":"type-page","3":"status-publish","4":"has-post-thumbnail","6":"page_category-linear-equations-videos","7":"page_category-math-advertising-group","8":"page_type-video","9":"content_type-practice-questions","10":"subject_matter-math"},"aioseo_notices":[],"_links":{"self":[{"href":"https:\/\/www.mometrix.com\/academy\/wp-json\/wp\/v2\/pages\/37252","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.mometrix.com\/academy\/wp-json\/wp\/v2\/pages"}],"about":[{"href":"https:\/\/www.mometrix.com\/academy\/wp-json\/wp\/v2\/types\/page"}],"author":[{"embeddable":true,"href":"https:\/\/www.mometrix.com\/academy\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.mometrix.com\/academy\/wp-json\/wp\/v2\/comments?post=37252"}],"version-history":[{"count":5,"href":"https:\/\/www.mometrix.com\/academy\/wp-json\/wp\/v2\/pages\/37252\/revisions"}],"predecessor-version":[{"id":279064,"href":"https:\/\/www.mometrix.com\/academy\/wp-json\/wp\/v2\/pages\/37252\/revisions\/279064"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/www.mometrix.com\/academy\/wp-json\/wp\/v2\/media\/91216"}],"wp:attachment":[{"href":"https:\/\/www.mometrix.com\/academy\/wp-json\/wp\/v2\/media?parent=37252"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}